Orthogonality
In order to derive some of the results included in this section, we make use of the product-to-sum trigonometric identities, given as follows:
Theorem: Orthogonality
Two nonzero functions, and are said to be orthogonal on if their inner product is given by
We are more interested in the so-called orthogonality relations a set of nonzero functions have: a sequence of functions is said to be tually orthogonal on if,
Next, we prove the orthogonality relations given by Theorem 1.1 for the set of functions . We want to prove that they are mutually orthogonal on ; to do that we will make use of the appropriate identity from (1.7a)-(1.7c) and relevant double angle formula relations. We start with the integral on the LHS of Eq. (1.9) where, here, and and :
We need to consider two cases separately for (i) and (ii) . For the case where , Eq. (1.10) becomes:
note that in going from left to right in Eq. (1.11), we made use of Eq. (1.5) since the function is an even function. To integrate the RHS of Eq. (1.11), we make use of the double angle formula . This gives:
Next, for the case , we need to make use of the sum-to-product identity given by Eq. (1.7c).
Note that the integrand is the product of two odd functions, which gives an even function. Integrating Eq. (1.14) with respect to , gives
Notice that in Eq. (1.15), we made use of Eq. (1.5) since we are integrating an even function from to . Firstly, we know that and therefore the denominator is well-defined. Secondly, observe that and are integers and hence and are also integers. It follows that and are zero-valued and the integral in Eq. (1.15) is zero. We have therefore shown that:
Equation (1.50) implies that the set of functions given by are mutually orthogonal on .
Similarly, we can show that the functions and are mutually orthogonal on giving rise to the following:
- if is integral and ;
- for any integers and ;
- if ;
- if is integral and .
These relations are useful in determining the Fourier coefficients.